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This is the seven ball siteswap 9797971. Filmed in the late 90s.

Here's the 5-ball siteswaps 771 and its pseudohalfshower 861, connected in a single run. Filmed 1996.

Here's the 5-ball siteswap 10 5 5 5 5 0 (a55550) done two different ways. First the 10 is a high throw, and the 0 is demonstrated with an open palm, and then the 10 is tossed to a kickup and back into the pattern.

Here's sort of the "Human Computer" way to deduce siteswap transition sequences between excited-state tricks. You map out the states, and look directly for ways to get from a state in one of the tricks to a state in the other.

This is the full file (not deinterlaced) of my world-record tie 11 flash.

This finishes the Throw Sequence method, for synch tricks.

11 throws, clean finish with 10 balls in the asynch fountain. 1995.

This is the best I could do that day, it just wasn't hitting.

I tried to qualify 9 on film back in 1995, but I only got 17 catches - twice!

The other run of 17 catches. Grrrrr!

Evolving routine with red solo cups and mouthstick.

Here's a non-trailer trailer for an upcoming mini-series of Boppo's Whiteboard ... namely, several different methods to calculate or deduce transition sequences between excited-state siteswap tricks. If you know the get-in and get-outs, that's enough to make transitions. If you know of or can find a trick that has states in common with the tricks you wish to transition between, that is enough to make transition sequences. If you know the states themselves and can find throws to convert between them, that too is enough. Also, if you can give the total arrival schedule, if you will, of the entire sequence you wish to have transitions within, that too enables you to deduce possible transition sequences. They all work for synch, too, but the last is maybe the best method for me.

The six-ball siteswap 999441. Note that there are 3, 2, and 1 throws of each different height, which have heights of 3^2, 2^2, and 1^1. The sum of the throws are then 3^3 + 2^3 + 1^1, which is the square of the third triangular number (1+2+3)^2. How about that? This works in general, by the way.